find the equation of line containing the points (1,2)(1,-2)
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Given ,
The equation of line passing through the points (1,2) and (1,-2)
We know that , the two point form is given by
Thus ,
y - 2 = (-2 - 2)/(1 - 1) × (x - 1)
y - 2 = -4/0 × (x - 1)
y - 2 = 1/0 × (x - 1)
0 = x - 1
x = 1
★ The equation of the line is x = 1
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Answer:
The equation of the line is x=1
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