Question

Find the equation of line equidistant from the lines x=-4 and x=8.

Answer 1

Required equation of line is also parallel to the y axis
find just mid point x=(-4+8)/2=2
equation is x=2

Answer 2

Answer:

Thus, x - 2 = 0 is the required equation of the line.

Step-by-step explanation:

Hi,

Given equation of lines x + 4 = 0 and x - 8 = 0 ,

Let the general point on the line be P(x, y).

Given that P(x, y) is equidistant from both the lines.

Distance of P(x, y) from line x + 4 = 0

= Distance of P(x, y) from line x - 8 = 0

| x + 4 | = | x - 8|

x + 4 = ± ( x - 8)

x + 4 = -x + 8

2x = 4

x = 2

Thus, x - 2 = 0 is the required equation of the line.

Hope, it helps !