Question

Find the equation of line having x-intercept =4, y-intercept =-3
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Answer 1

$\huge{\underline{\sf{\red{Answer}}}}$

Given:

X-intercept = 4

Y-intercept =-3

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$\huge{\underline{\underline{\green{\tt{Formula}}}}}$

$\dfrac{x}{a} + \dfrac{y}{b} = 1$

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$\huge{\underline{\tt{SoluTion}}}$

$\dfrac{x}{4}+ \dfrac{y}{-3} =1 \\ \\ \implies -3x+4y=-12 \\ \\ \implies \boxed{3x-4y-12=0}$

Answer 2

$\huge{\underline{\underline{\mathfrak{Answer}}}}$

$\huge{\underline{\underline{\mathfrak{SOLUTION}}}}$

GIVEN:

$x - intercept = 4$

$y - intercept = - 3$

FORMULA USED :

$\frac{x}{a} + \frac{y}{b} = 1$

$\frac{x}{4} + \frac{y}{ - 3} = 1$

$= > - 3x + 4y = - 12$

$= > 3x - 4y - 12 = 0$

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$\huge{\underline{\underline{\mathfrak{Thank you}}}}$