Question

find the equation of line parallel to the line 3 x minus 4 Y + 2 = 0 passing through - 2, 3​

Answer 1

Answer---> 3x - 4y + 18 = 0

To find----> Equation of line parallel to the line

3x - 4y + 2 = 0 and passing through ( - 2 , 3 ).

Solution----> We know that if equation of a line is

ax + by + c = 0

Then , equation of line parallel to above line is

ax + by + λ = 0

Now , equation of given line is

3x - 4y + 2 = 0 .......................( 1 )

By applyibg above concept , equation of line parallel to line ( 1 ) is ,

=> 3x - 4y + λ = 0 ......................,..( 2 )

Now , line ( 2 ) passes through ( - 2 , 3 )

=> 3 ( - 2 ) - 4 ( 3 ) + λ = 0

=> - 6 - 12 + λ = 0

=> - 18 + λ = 0

=> λ = 18

Putting λ = 18 , in equation ( 2 ) , we get, required equation of line,

=> 3x - 4y + 18 = 0