Question

find the equation of line passing through ( 2,0) and perpendicular to the line 3+4=1​

Answer 1

Answer:

4x-3y-8=0

Step-by-step explanation:

let P( 2,0) is perpendicular to the line 3x+4y=1​

3x+4y=1​

4y = -3x+1

y = -3x/4 + 1/4

slope m = -3/4

therefore the slope of P = 4/3

y-0 = 4/3(x-2)

3y =4x-8

4x-3y-8=0

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