Math, asked by pg0995310, 4 months ago

find the equation of line passing through (2,---3) and parell of the line 4x-y+7=0​

Answers

Answered by riya23282
0

Answer:

line is parallel to 4x-y+7=0

so it will be of form 4x-y+c=0

as it passed through (2,-3) so 4×2-(-3)+c=0

8+3+c=0

c=-11

so required equation is

4x-y-11=0

Answered by 2008shrishti
29

Answer:

line is parallel to 4x-y+7=0

so it will be of form 4x-y+c=0

as it passed through (2,-3) so 4×2-(-3)+c=0

8+3+c=0

c=-11

so required equation is

4x-y-11=0

Step-by-step explanation:

Hope this answer will help you.✌️

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