find the equation of line passing through (2,---3) and parell of the line 4x-y+7=0
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Answered by
0
Answer:
line is parallel to 4x-y+7=0
so it will be of form 4x-y+c=0
as it passed through (2,-3) so 4×2-(-3)+c=0
8+3+c=0
c=-11
so required equation is
4x-y-11=0
Answered by
29
Answer:
line is parallel to 4x-y+7=0
so it will be of form 4x-y+c=0
as it passed through (2,-3) so 4×2-(-3)+c=0
8+3+c=0
c=-11
so required equation is
4x-y-11=0
Step-by-step explanation:
Hope this answer will help you.✌️
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