Question

find the equation of line passing
through (3,-4) and having slope
3/2
is-​

Answer 1

Answer:

We should use point-slope form to solve this.

Here, x1=3, y1=-4 and slope, m=3/2.

Point slope form:

(y-y1)=m(x-x1)

(y-{-4})=3/2 (x-3)

y+4=3/2 (x-3)

2y+8=3x-9

3x-2y=17

is the required equation.

Hope it helps !

Answer 2

EXPLANATION.

Equation of line passing through = (3,-4).

Slope of the line = 3/2.

As we know that,

Equation of line.

⇒ (y - y₁) = m(x - x₁).

Put the value in equation, we get.

⇒ (y - (-4)) = 3/2(x - 3).

⇒ (y + 4) = 3/2(x - 3).

⇒ 2(y + 4) = 3(x - 3).

⇒ 2y + 8 = 3x - 9.

⇒ 2y - 3x + 17 = 0.

                                                                                                                               

MORE INFORMATION.

Equation of straight line parallel to axes.

(1) = Equation of x-axis ⇒ y = 0.

(2) = Equation of a line parallel to x-axes at a distance of b ⇒ y = b.

(3) = Equation y-axis ⇒ x = 0.

(4) = Equation of a line parallel to y-axes and at a distance of a ⇒ x = a.