Question

Find the equation of line passing through origin which is included to positive direction of x axis at an angle of 60°.​

Answer 1

Step-by-step explanation:

Given:-

angle = 60°

Point = Origin = (0,0)

To find:-

Find the equation of line passing through origin which is included to positive direction of x axis at an angle of 60°.

Solution:-

Given that

The origin = (0,0)

The angle at positive direction of x-axis = 60°

Slope of an inclination of a line of angle A at positive at x-axis is m = Tan A

Slope = m = Tan 60°

m = √3

Given point = (0,0)

Let (x1, y1)=(0,0)=>x1=0 and y1=0

We know that

The line passing through the point (x1, y1) with the slope m is y-y1 = m (x-x1)

=> y - 0 = √3 ( x-0)

=> y = √3 (x)

=> y = √3 x

=> √3x - y = 0

Answer:-

The equation of a line for the given problem is √3x - y = 0

Used formulae:-

• Slope of an inclination of a line of angle A,positive at x-axis is
• m =Tan A
• The line passing through the point (x1, y1) with the slope m is
• y-y1 = m (x-x1)
• Coordinates of The Origin = (0,0)
• Tan 60°=√3