Find the equation of line passing through point (-2,0) and equally inclined to the co-ordinate axes.
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We have a point (-2,0)
For a line through this point, we have
y-0=m (x-(-2))
Where m=slope=1 for equal inclination with both axes.
Therefore, equation of the line is x-y+2=0
Have a nice day!
For a line through this point, we have
y-0=m (x-(-2))
Where m=slope=1 for equal inclination with both axes.
Therefore, equation of the line is x-y+2=0
Have a nice day!
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