Find the equation of line passing through the mid point of (1,2) and (3,-1) and parallel to the line 3x-4y+5=0.
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Answered by
1
Answer:3x-4y-4
Step-by-step explanation:
Midpoint of (1,2) and (3,-1) is (2,0.5) by mean method .
As it is parallel to 3x-4y+5 its eqn will be 3x-4y+c .
Put (2,0.5) in 3x-4y+c and you will find c.
Answered by
4
Heya!!
Co-ordinates of mid points are x1 = 1 + 3 / 2 = 2
y1= 2 - 1 / 2 = 1 / 2
Slope of given line is m = 3 / 4
equation of required line is
y - y1 = m ( x - x1 )
y - 1 / 2 = 3 / 4 ( x - 2 )
Co-ordinates of mid points are x1 = 1 + 3 / 2 = 2
y1= 2 - 1 / 2 = 1 / 2
Slope of given line is m = 3 / 4
equation of required line is
y - y1 = m ( x - x1 )
y - 1 / 2 = 3 / 4 ( x - 2 )
yoge2390:
you are wrong x= (1+3)/2=4/2=2
no problem it is just a culculation error
yup
how did you find m
slope of striagh line ax + by +c = 0 is - a / b
thanks
welcome!☺️
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