Question

Find the equation of line passing through the point (0,-2) (3,4).​

Answer 1

Answer:

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Step-by-step explanation:

Let the equation of circle be-

x2+y2+2gx+2fy+c=0.....(1)

Given that the circle passes through the points (3,4),(3,2) and (1,4).

Therefore,

(3)2+(4)2+2g(3)+2f(4)+c=0

⇒9+16+6g+8f+c=0

⇒6g+8f+c+25=0.....(2)

(3)2+(2)2+2g(3)+2f(1)+c=0

⇒9+4+6g+2f+c=0

⇒6g+2f+c+13=0.....(3)

(1)2+(4)2+2g(1)+2f(4)+c=0

⇒1+16+2g+8f+c=0

⇒2g+8f+c+17=0.....(4)

Subtracting equation (3) from (2), we have