Question

Find the equation of line passing through the point (0,-2) (3,4)​

Answer 1

Given that,

4x+3y=1 ⟶(1)

3x−y+9=0⟶(2)

Solving the equations simultaneously, we get

4x+3y=1×1

3(3x−y)=−9×3

4x+3y=1

9x−3y=−27

13x=−26

x=−2

y=−3

B(−2,−3)

∴ Slope of the passing through the point (0,−2) and (−2,−3)

⇒m=

−2−0

−3+2

=

−2

−1

⇒m=

2

1

So, the equation of line is given as,

y−y

1

=m(x−x

1

)

⇒ (y+2)=

2

1

(x−0)

⇒ 2y+4=x

⇒ x−2y+4=0

Answer 2

Answer:

ans is 0

Step-by-step explanation:

Given that,

4x+3y=1 ⟶(1)

3x−y+9=0⟶(2)

Solving the equations simultaneously, we get

4x+3y=1×1

3(3x−y)=−9×3

4x+3y=1

9x−3y=−27

13x=−26

x=−2

y=−3

B(−2,−3)

∴ Slope of the passing through the point (0,−2) and (−2,−3)

⇒m=

−2−0

−3+2

=

−2

−1

⇒m=

2

1

So, the equation of line is given as,

y−y

1

=m(x−x

1

)

⇒ (y+2)=

2

1

(x−0)

⇒ 2y+4=x

⇒ x−2y+4=0