Question

find the equation of line passing through the point (1,1) and parallel to the line 4x+4y+7=0​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given Find the equation of line passing through the point (1,1) and parallel to the line 4x+4y+7=0

• Let the equation of line AB be 4x + 4y + 7 = 0 and point be P(1,1)
• We need to find slope of the line.
• 4x + 4y + 7 = 0
• 4x + 7 = - 4y
• 4x + 7/ - 4 = y
• Or – 4x – 7 / 4 = y  
• Or – x  - 7/4 = y
• Or y = - x – 7/4
• This is in the form of y = mx + c
• Slope of line m = - 1
• Now equation of the line passing through the point P(1,1) will be
• Equation of the line (y – yo) = m (x – xo)
•                               (y – 1) = -1 (x – 1)
•                           So y – 1 = - x + 1
•                         Or y – 1 + x – 1 = 0
•                      Or x + y – 2 = 0

Therefore the required equation of line is x + y – 2 = 0

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https://brainly.in/question/12203603