Find the equation of line passing through the point (2,-3) and having the slope of 2.
Answers
Step-by-step explanation:
Given line equations are,
7x+6y=71⇒28x+24=284 ......(1)
5x−8y=−23⇒15x−24y=−69 ....(2)
On adding (1) and (2), we have
43x=215
x=5
From (2), we get
8y=5x+23=25+23=48
⇒y=6
Hence, the required line passes through the point (5,6).
Given, 4x−2y=1
2y=4x−1
y=2x−(1/2)
So, the slope of this line =2
And, the slope of the required line =−1/2
[As the lines are perpendicular to each other]
Thus, the required equation of the line is
y−y
1
=m(x−x
1
)
y−6=(−1/2)(x−5)
2y−12=−x+5
x+2y=17
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