Question

find the equation of line passing through the point 4, 5 and perpendicular to line 7×-5y= 120

Answer 1

Answer:

5x-7y+15=0

Step-by-step explanation:

slope of given line =-7/-5=7/5

slope of required line=5/7

as the line passes through 4,5 therefore x1=4 and y1=5

by using point slope formula

y-y1=m(x-x1)

y-5=5/7(x-4)

7(y-5)=5(x-4)

7y-35=5x-20

by rearranging and solving,we get equation of required line i.e

5x-7y+15=0

hope it will be helpful