Question

find the equation of line passing through the point of intersection of line x+y-2=0 and 2x-3y+4=0 and making intercept 3 on the x axis​

Answer 1

Answer:

Step-by-step explanation:

Given lines x−y−1=0 to 2x−3y+1=0

Intersection point  

→x=y+1

→2(y+1)−3y+1=0

→2y+2−3y+1=0

→3=y

→x=3+1=4

Point (4,3)

(i) parallel to x-axis and passes through (4,3)y=3

(ii) parallel to y-axis and passes through (4,3)x=4

(iii) parallel to 3x+4y=14 any line parallel to 3x+4y can be written as  

→3x+4y=c

→3(4)+4(3)=c

→24=c

so, equation of line =3x+4y=24