Find the equation of line passing through the point of intersection of the lines 2x-3y-1=0 and x-y=2 that passes through (1,1)
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Answer:
Hence,equationofliney=−4x+2
Step-by-step explanation:
Letequationofliney=mx+c→(i)
Bysolvingn−y=1and2x+3y=4
x−y−1=0
2x+3y−4=0
⇒
7
x
=
2
y
=
5
1
x=
5
7
andy=
5
2
distancefromapoints(2,−3)and(h
1
)online
y=mx+caresame
⇒
1+m
2
∣−3−2m−c∣
=
1+m
2
∣1−mx−c∣
⇒3=2m+c=m+c−1
m=−4
Putx=
5
7
,y=
5
2
andm=−4inequation(i)
⇒
5
2
=−4×
5
2
+c,c=2
Hence,equationofliney=−4x+2
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