Question

Find the equation of line passing through the point of intersection of the lines 2x-3y-1=0 and x-y=2 that passes through (1,1)​

Answer 1

Answer:

Hence,equationofliney=−4x+2

Step-by-step explanation:

Letequationofliney=mx+c→(i)

Bysolvingn−y=1and2x+3y=4

x−y−1=0

2x+3y−4=0

⇒  

7

x

​  

=  

2

y

​  

=  

5

1

​  

 

x=  

5

7

​  

andy=  

5

2

​  

 

distancefromapoints(2,−3)and(h  

1

)online

y=mx+caresame

⇒  

1+m  

2

 

​  

 

∣−3−2m−c∣

​  

=  

1+m  

2

 

​  

 

∣1−mx−c∣

​  

 

⇒3=2m+c=m+c−1

m=−4

Putx=  

5

7

​  

,y=  

5

2

​  

andm=−4inequation(i)

⇒  

5

2

​  

=−4×  

5

2

​  

+c,c=2

Hence,equationofliney=−4x+2

​