find the equation of line perpendicular to 5x-2y=8 and which passes through the mid pont of the line joining (2,3)and(4,5)
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Answer:
midpoint so point is (3,4)
and they are perpendicular
slope m² is
5x-2y=8m¹=-a/b=-5/-2=5/2
and m¹*m²=-1
m²=-2/5
point slope form : required eq is 2x+5y=26
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