Question

find the equation of line that is parallel to 2x-5y+3=0 and has x intercept 4 units​

Answer 1

Answer:

Given line: 2x+5y−7=0

5y=−2x+7

y=(5−2)x+57

So, the slope is 5−2

Hence, the slope of the line that is parallel to the given line will be the same, m=5−2

Now, the mid - point of the line segment joining point (2,7) and (−4,1) is 

(2(2−4),2(7+1))=(−1,4)

Thus, the equation of the line will be

y−y1=m(x−x1)

y−4=(5−2)(x+1)

5y−20=−2x−2

2x+5y=18