Question

Find the equation of line through (3,2) and making an intercept a and b on the x-axis and y-axis respectively such that a-b=2​

Answer 1

$\huge{\underline{\sf{\red{Answer}}}}$

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Given:

★ Line Pass through point (3,2)

★ Slope of line wil be -ve since a and b are intercepts

★ a-b=2

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$\huge{\underline{\underline{\green{\tt{Formula}}}}}$

$\dfrac {x}{a} +\dfrac {y}{b} =1$

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$\huge{\underline{\tt{SoluTion}}}$

$\dfrac {3}{a} + \dfrac {4}{b} = 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{(a=b+2)} \\ \\ \implies\dfrac {3}{b+2} + \dfrac {4}{b} =1 \\ \\ \implies 3b+4b+8 =b^2 +2b \\ \\ \implies b^2 -5b-8 \\ \\ b=2 \\ \\ a=2+2 =4 \\ \\ \dfrac {x}{4} + \dfrac {y}{2} =1 \\ \\ \impies \boxed{x+2y-4}$

Answer 2

Answer:

Given:

★ Line Pass through point (3,2)

★ Slope of line wil be -ve since a and b are intercepts

★ a-b=2

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\huge{\underline{\underline{\green{\tt{Formula}}}}}

Formula

\dfrac {x}{a} +\dfrac {y}{b} =1

a

x

+

b

y

=1

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\huge{\underline{\tt{SoluTion}}}

SoluTion