Question

Find the equation of line through the intersection of x-2y+1=0 and 2x+3y-2=0 and having x-intrcept equal to 3 ​

Answer 1

Answer:

$\frac{x}{3} + \frac{5y}{3} = 1$

Step-by-step explanation:

x-2y+1=0............(1)

2x+3y-2=0........(2)

solve 1 and 2nd

x=1/7, y=4/7

let the equation of required line

x/a+y/b=1........(3)

where a and b are the intercept of x and y axis respectively.

here a= 3 (given)

and the above line is passing throught(1/7,4/7)

$\frac{1}{21} + \frac{4}{7b} = 1$

solve it,

$b = \frac{3}{5}$

now put all values in equations 3

$\frac{x}{3} + \frac{5y}{3} = 1$