Find the equation of line through the point of intersection of 3 x + 4 y - 7 is equal to zero and x minus y + 2 is equals to zero and whose slope is 5
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3x+4y-7=0 _(1)
x-y+2=0 _(2)
from 1 and 2 by elimination method
(3x+4y-7=0)×1
(x-y+2)×3
3x+4y-7=0
-3x-3y+6=0
+ -
7y-13=0
7y=13
y=13/7
put y=13/7 in 2 equation
x-13/7=-2
(7x-13)/7=-2
7x-13=-14
7x=-1
x=-1/7
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