find the equation of line which cuts off intercepts 4 and -6 from x-axis and y-axis respectively *
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Equation of straight line cutting intercepts a and b from x and y axis respectively is x/a + y/b = 1. Here a = 4 and b = -3 (given). Hence equation of the straight line is
x/4 + y/-3 = 1 => (-3x +4y)=-12
=> 3x - 4y =12
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