find the equation of line which has positive y intercept 4 units and is parallel to the line 2x -3y=7 also find the pt where it cuts the x axis
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2x - 3y = 7
the line which has positive Y intercept 4 units is parallel to line 2x - 3y = 7.
it means that,
2x - 3 Y = 7 will also verify the equation made by the second line.
putting the value of Y equal to 4 units in equation 2 X - 3y = 7.
2 x - 12 = 7.
2x = 19.
X = 9.5
so X intercept for this equation which have positive intercept of Y equal 4 units is 9.5.
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the line which has positive Y intercept 4 units is parallel to line 2x - 3y = 7.
it means that,
2x - 3 Y = 7 will also verify the equation made by the second line.
putting the value of Y equal to 4 units in equation 2 X - 3y = 7.
2 x - 12 = 7.
2x = 19.
X = 9.5
so X intercept for this equation which have positive intercept of Y equal 4 units is 9.5.
°°°LIKE IF U R AGREE°°°
PLEASE MARK IT AS A BRAINLIEST ANSWER.
Akv2:
like guys if you are agree
Answered by
16
Let the needed line be y=mx+c
Given c=4
Since the line is parallell to y=2x/3 -7/3 The must have Same slope
i.e m=2/3
y=2x/3 +4
2x-3y+12=0 This is the required line.
Given c=4
Since the line is parallell to y=2x/3 -7/3 The must have Same slope
i.e m=2/3
y=2x/3 +4
2x-3y+12=0 This is the required line.
Oops We can get x intercept when y=0
By putting y=0 we get x=-6
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