Question

Find the equation of line which is passing through point (-5,6) and with inclination of 150 degree.​

Answer 1

SOLUTION

TO DETERMINE

The equation of line which is passing through point (-5,6) and with inclination of 150°

CONCEPT TO BE IMPLEMENTED

The equation of line which is passing through point (a,b) and with inclination of θ is

y - b = tanθ ( x - a )

EVALUATION

Here it is given that the required line is passing through point (-5,6) and with inclination of 150°

So the equation of the line is

y - 6 = tan150° ( x + 5 )

tan150°

= tan( 2 × 90° - 30° )

= - tan 30°

$\displaystyle \sf{ = - \frac{1}{ \sqrt{3} } }$

Hence the required equation of the line is

$\displaystyle \sf{ (y - 6)= - \frac{1}{ \sqrt{3} }(x + 5) }$

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