Question

Find the equation of line which passes through (3,-1) and with inclination of 60⁰​

Answer 1

Answer:

y = √3x - (3√3 +1)

Step-by-step explanation:

m= tan 60° = √3

Eqn. of line => (y-y¹) = m(x-x¹)

=> y-(-1) = √3(x-3)

=> y+1 = √3x - 3√3

=> y = √3x - (3√3 +1)