Question

Find the equation of line which passes through point of intersection of the lines x-y-1=0 and 2x-3y+1=0 and is parallel to the line 3x+4y-15=0

Answer 1

Answer:

Step-by-step explanation:

x-y=1...(1)

2x-3y=-1...(2)

Multiplying (1) by 2,

2x-2y=2

Subtracting (2) from (1),

y=3

Using y=3 in (1),

x-3=1

x=4

Therefore, point of intersection = (4,3)

It is parallel to 3x+4y=15

4y=15-3x

y=15/4-3x/4

Therfore (m) slope = -3/4

Equation

-3/4=(y-3)/(x-4)

4y-12= -3x+12

3x+4y=24

3x+4y-24=0. (Ans)