Question

Find the equation of line which passes through the point of intersection
3x + 2y – 6 = 0, x + y + 1 = 0 and the point A(2,1).​

Answer 1

Step-by-step explanation:

3x+2y-6=0.

x+y=0

___________

4x+3y-7=0

Answer 2

Answer:

5x+3y-13=0

Step-by-step explanation:

3x+2y-6=0&x+y+1=0, it's equation is of the form u+kV=0

=(3x+2y-6)+k(x+y+1)=0

=(3+k)x+(2+k)y+(-6+k)=0

this line passes through the point A(2,1)

=(2,1)satisfy this equation

=(3+k)(2)+(2+k) (1)+(-6+k)=0

=4k+2=0

=k=-1/2

=the equation of the required line is

(3x+2y-6)+(-1/2)(x+y+1)=0

5x+3y-13=0

plz Mark as brainleast