Question

Find the equation of lines
for which make intercepts
-3 and 2 on the x-axis and
y axis respectively.​

Answer 1

${\huge{\underline{\underline{\rm{\bold{QuestiOn:}}}}}}$

Find the equation of the line which cuts off intercepts -3 and 2 on the x-axis and y-axis respectively.

${\huge{\underline{\underline{\rm{\bold{SolutiOn:}}}}}}$

${\bf{\red{Given\:that:}}}$

Let a and b be the intercepts on x-axis and y-axis respectively.

Then, x-intercept is a = -3

y-intercept is b = 2

${\bf{\boxed{\blue{Formula\:Used:}}}}$

We know that formula for intercept form of a line is given by:

$\huge \frac{x}{a} + \frac{y}{b} = 1 \\ \huge\frac{x}{ - 3} + \frac{y}{2} = 1$

2x - 3y = -6

2x - 3y +6 = 0

$\bf{\green{Hence,2x-3y+6 is\: the\: required\: equation\: of \:the\: given\: line.}}$