Question

find the equation of locus of a point equidistant from A(2,0) and the y axis.b.​

Answer 1

Answer:

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Step-by-step explanation:

Let the point be P(h,k)

Given,

P is equidistant from A(2,0) and the Y axis

⇒

(h−2)

2

+K

2

=h

⇒(h−2)

2

+K

2

=h

2

[Squaring]

⇒h

2

+4−4h+K

2

=h

2

⇒K

2

=4(h−1)

Replacing (h.k) with (x,y) we get

y

2

=4(x−1)

Answer 2

Answer:

Given: P = (x,y), A = (2,0), B = (0,y)
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