Question

Find the equation of locus of a point, the difference of whose distance of whose distances from (-5,0) and (5,0) is 8

Solve for P(x,y) and then verify it with Q (x1,y1)

Answer 1

Answer:

Step-by-step explanation:

Let p( x, y) be any point in the locus. A(-5,0) and B(5,0) are fixed point

according to question,

(AP) ^2 +(PB) ^2 = 8

or, (x+5)^2 +(y -0)^2 +(x-5)^2 +(y-0)^2=8

or, x^2+ 25 +y^2 +x^2 - 25 +y^2 = 8

or, 2x^2 + 2y^2 = 8

or, 2x^2 + 2y^2 - 8 =0

or, x^2 + y^2 - 8 =0 is required equation.