Find the equation of locus of a point which is at a distance 5 from A (4, -3)
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Answer:
d2 = 4y
x2 + y2 = 4y
x2 + y2 - 4y = 0
x2 + y2 - 4y + 4 = 4
x2 + (y - 2)2 = 22
this is a circle centered at (0, 2) with a radius of 2.
Some solutions:
(2, 2), (-2, 2), (0, 0), and (0, 4)
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Answer:
Step-by-step explanation:
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