Question

find the equation of locus of a point which is at a distance 5 from A(4,-3)

Answer 1

Step-by-step explanation:

Let the point be B(h,k) , the fixed point be A(−2,3) and AB=5

AB=√(h-4)²+(k+3)²

(AB)²=(h-4)²+(k+3)²

25=(h-4)²+(k+3)²

For locus replace h—>x,k–>y

(x-4)²+(y+3)²=25 is a circle with radius 5 and centre (4,-3)