Question

Find the equation of locus of a point which is at a distance 5 from A (4, -3)​

Answer 1

Answer:

Let P(x,y)P(x,y) be the point Its distance from A(−5,0)A(−5,0) is

PA=(x+5)2+y2−−−−−−−−−−−√PA=(x+5)2+y2

its distance from the line x=−165x=−165 is PH=∣∣∣x+165∣∣∣PH=|x+165|

PA=54PH→PA2=2516PH2PA=54PH→PA2=2516PH2

so we have

(x+5)2+y2=2516(x+165

Answer 2

answer in the attchment

hope itz help u❣️❣️❣️