Question

find the equation of locus of a point which is at a distance 3 units from the point (3,-1)​

Answer 1

Let the point be P ( h,k ) , the fixed point be Q (3, -1) and PQ = 3

PQ = √ ( h+ 3)² + ( k-1) ²

(PQ)² = ( h+ 3) ² + (k -1)²

9 = (h+3) ² + (k-1)²

for locus replace h → x , k → y

( x + 3)² + (y - 1)² = 9

is a circle with radius 3 and center ( 3, -1 )

Thank you :)