Question

Find the equation of locus of a point which is equidistant from the points (2,3) and (4,5)

Answer 1

Step-by-step explanation:

hope it is helpful to you

Answer 2

Answer:

x+y=7

Step-by-step explanation:

let point P be P(x,y)

by question,

PA=PB

or,$\sqrt{(x-2)^2+(y-3)^2$ = $\sqrt{(x-4)^2+(y-5)^2$

or,$x^2+4-4x+y^2+9-6x=x^2+168y+x^2+25-10y$

or,4x+4y=28

or, x+y=7