Find the equation of locus of a point which is equidistant fron
Find the equation of locus of a point equidistant from A (2.0) and the Y-axis.
Answers
Answered by
1
Let the point be P(h,k)
Given,
P is equidistant from A(2,0) and the Y axis
⇒
(h−2)
2
+K
2
=h
⇒(h−2)
2
+K
2
=h
2
[Squaring]
⇒h
2
+4−4h+K
2
=h
2
⇒K
2
=4(h−1)
Replacing (h.k) with (x,y) we get
y
2
=4(x−1)
Answered by
1
Answer:
Given: P = (x,y), A = (2,0), B= (0,y)
⇒ PA = PB
- See attachments for Full answer.
Attachments:
Similar questions