Question

Find the equation of locus of a point which is equidistant from A(2,0) and the Y-axis
​

Answer 1

The location of the point which is equidistant from A(2,0) and Y axis is (1,0)

Answer 2

Answer:-

Let the point be P(h,k)

Given,

P is equidistant from A(2,0) and the Y axis

⇒(h−2)2+K2

​=h

⇒(h−2)2+K2=h2              [Squaring]

⇒h2+4−4h+K2=h2

⇒K2=4(h−1)

Replacing (h.k) with (x,y) we get

y2=4(x−1)

refer the attachment..!!

Hope it helps..!!

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