Find the equation of normal to the circle x²+y²-4x-6y+11=0 at (3,2)
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as x = 3 , y = 2
(3)² + (2)² - 4(3) - 6(2) + 11 = 0
9 + 4 - 12 - 12 + 11 = 0
13 + 11 - 24 = 0
24 - 24 = 0
0 = 0
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