Math, asked by komalpreet442006, 10 months ago

FINd the equation of normal to the curve y=x cube +x square-11x +15 where normal is parallel to the line x-3y+1=0

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Answered by Anonymous
3
.<marquee>the equation of normal to the curve y=x cube +x square-11x +15 where normal is parallel to the line x-3y+1=0</marquee>
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