Question

find the equation of one of the sides of an isosceles right angled triangle whose hypotenuse is given by 3x + 4y =4 and the opposite vertex of the hypotenuse is (2,2)
please answer it for 6 marks

Answer 1

(3x+4y)²=x²+y²

(3x)²+(4y)²+2×3x×4y=x²+y²

9x²+4y²+24xy=x²+y²

9x²-x²+4y²-y²=24xy

8x²+3y²=24xy

Divide both sides by xy

8x²/xy+3y²/xy=-24xy

8x/y+3y/x=-24

put.x/y=x

And y/x=y

There four the eq.is

8x+3y=-24

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