Question

find the equation of parabola with vertex 1,-2 axis parallel to x axis and passing through (-1/2,-4)​

Answer 1

Answer:

(x-h)^2 = 4a(y-k)    

where  (h,k) - is the vertex

(x,y) - points along the.

Step-by-step explanation:

Since the axis of the parabola is parallel to the y-axis, it indicates that the parabola either opens upward or downward.

For parabola that opens upward/downward, the standard equation is:

(x-h)^2 = 4a(y-k)    

where  (h,k) - is the vertex

         (x,y) - points along the...