Question

find the equation of parallel to the line 3x -y+5 and passing through (3,-2)​

Answer 1

Answer:

$\bf\red{3x-y-11=0}$

Step-by-step explanation:

It is given, an equation of line,

3x - y + 5 = 0

=> y = 3x + 5

But, we know that,

y = mx + c is slope intercept form of line,

where,

m is the slope and,

c is the intercept

So considering this in given equation of line,

we get,

=> m = 3

Now, A point is given (3,-2)

Let it be (x1,y1) = (3,-2)

Now, we have to find the equation of the line parallel to the given line and passing through the given point.

We know that, slope-point form of line is given by,

( y - y1) = m( x - x1 )

Here, it is parallel to the given line ,

therefore,

the slope will same as of the given line, i.e.,

m = 3 and (x1,y1) = (3,-2)

Putting the values, we get

=> [y - (-2)] = 3 ( x - 3 )

=> y + 2 = 3 ( x -3 )

=> y + 2 = 3x - 9

=> 3x - y -11 = 0

Hence, the required equation of line is

3x - y - 11 = 0

Answer 2

$\huge{\textbf{\underline{\red{Solution is attached here.}}}}$