find the equation of perpendicular bisector of the line segments joining(3,2) and (7,6)
Answers
Answered by
8
Mid Pt.-> (5,4)
Slope of given line is 6-2/7-3 = 1
slope of reqd. perpendicular is -1
.'. by slope point form,
y-5=-1(x-4)
y-5=4-x
x+y-9=0...... reqd eqn
Slope of given line is 6-2/7-3 = 1
slope of reqd. perpendicular is -1
.'. by slope point form,
y-5=-1(x-4)
y-5=4-x
x+y-9=0...... reqd eqn
Chandransh:
But the ans is coming x+y=9
yes, Sorry for the mistake.
Answered by
4
Slope of line joining the points is 1
So slope of perpendicular bisector is - 1
Midpoint is (5,4)
Y-4=-X+5
=>X+Y-9=0
So slope of perpendicular bisector is - 1
Midpoint is (5,4)
Y-4=-X+5
=>X+Y-9=0
But the ans is coming x+y=9
Is the answer given?
You can check the points by drawing on graph paper then you can be sure...
Sorry it was my fault :)
Its ok but how can i do correctly
I corrected the answer...
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