Question

find the equation of perpenticular bisector of the line joining points A ( 2, 3) and b (6, - 5)​

Answer 1

Answer:

x - 2 y - 6 = 0

Step-by-step explanation:

given--->end points of a line A(2,3)andB

-----------

(6 ,-5)

To find ---->equation of perpendicular

-------------

bisector of AB

solution ---->

--------------

let perpendicular bisector of AB is CD and it intersect AB at M

now

coordinate of mid point of line joining points (a, b) and (c, d) is

a+d b+c

(----------- , ---------)

2 2

applying this

2+6 3-5

coordinate of M=(----------, ---------)

2 2

=( 4 , -1)

now slope of line joining the points (a, b) (c, d) is

d - b

= ---------

c - a

-5-3

now slope of AB=------------

6-2

-8

=-------------=-2

4

since AB and CD are perpendicular

slope of AB×slope of CD=-1

-2 × slope of CD = -1

-1 1

slope of CD= -------=------

-2 2

now equation of line passing through a point (a, b) and whose slope is m

(y-b) = m (x-a)

now equation of perpendicular bisector CD of AB

1

{y-(-1)}= ------(x-4)

2

1

y + 1 = ------ (x - 4)

2

2(y+1) = x - 4

2y + 2 = x - 4

x - 2 y - 6 = 0

Answer 2

Answer:

firstly calculate the mid pt of a and b

then find slope of it after that revrse it

then u got a slooe of a new line x -2y-6=0