Math, asked by jackeider12, 1 month ago

Find the equation of plane passing through the points P(1, 1, 1), Q(3, -1, 2), R(-3, 5, -4).

(a) x + 2y = 0

(b) x – y = 2

(c) -x + 2y = 2

(d) x + y = 2​

Answers

Answered by princepawaiya021
0

Answer:

p(x) = 2r+r-2r-1, g(x)=x+1

(ü) P(x)=x+3x+3.r+1, g(x)=x+2

(ii) p(x)=x-4r+x+6, g(x)=x-3

3. Find the value of k, if r - 1 is a factor of p(x) in each of the following cases:

(1) p(x)= x +x+k

(i) p(x) = 2x² + kr +

(iii) P(x) = kr 3r+1

(iv) p(x) = kr - 3.r+k

Factorise :

(1) 12r-7x+1

(i) 2r+7x+3

(i) 6r+ 58 - 6

(iv) 3r-x-4

Factorise :

(1) r- 2r-x+2

(ii) r- 3.r- - 9x-5

(i) rº+13r-+32r+20

(iv) 2x + y2 - 2y - 1

same my question

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