find the equation of straight line if it passes through point(4,1)and makes intercepts on the axes the sum whose length is 9
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Heya!!
General Equation of line making intercept a and b on co-ordinate axis is
x/a + y/b = 1
Exp:-
x = 4 and y = 1 Given
a + b = 9 Given
a = 9 - b
=> 4/9 - b + 1 / b = 1
=> 4b + 9 - b = b ( 9 - b )
=> 3b + 9 = 9b - b²
=> b² - 6b + 9 = 0
=> b² - 3b - 3b + 9 = 0
=> b ( b - 3 ) -3 ( b - 3 ) = 0
=> b = 3
Now, put value of b in this equation
a + b = 9 we get a = 6
So, equation of line passing through points ( 4,1 ) and sum of whose intercepts is 9 is
x/6 + y/3 = 1
3x + 6y = 18
General Equation of line making intercept a and b on co-ordinate axis is
x/a + y/b = 1
Exp:-
x = 4 and y = 1 Given
a + b = 9 Given
a = 9 - b
=> 4/9 - b + 1 / b = 1
=> 4b + 9 - b = b ( 9 - b )
=> 3b + 9 = 9b - b²
=> b² - 6b + 9 = 0
=> b² - 3b - 3b + 9 = 0
=> b ( b - 3 ) -3 ( b - 3 ) = 0
=> b = 3
Now, put value of b in this equation
a + b = 9 we get a = 6
So, equation of line passing through points ( 4,1 ) and sum of whose intercepts is 9 is
x/6 + y/3 = 1
3x + 6y = 18
sanskriti2061:
thank u zakirkashmiri 786
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Answer:
x+2y=6 is the equation of straight line
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