Question

find the equation of straight line passing through 5, - 3 and 7 - 4​

Answer 1

Step-by-step explanation:

Here we should use the two point formula:y-y¹/y²-y¹=x-x¹/x²-x¹

by using this formula,

y+3/-4+3=x-5/7-5

then,

2y+6=-x+5

so,

x+2y+1=0

Answer 2

Concept:

slope=(y₂-y₁)/x₂-x₁)

The equation of a line using slope and one point,

(y-y₁)=m(x-x₁)

Given:

A(5,-3) and B(7,-4).

Find:

the equation of straight line passing through A(5, - 3) and B(7, - 4​)

Solution:

To find a equation of the line, we need to things, first is slop and one point on the line.

Let x₁=5,y₁=-3

      x₂=7 ,y₂=-4

So first we need to find the slope

slope=(y₂-y₁)/x₂-x₁)

         =(-4+3)/(7-5

          =-1/2

THe equation of line:

(y-y₁)=m(x-x₁)

⇒y+3=-1/2(x-5

⇒2y+6=-x+5

⇒x+2y=-1

Therefore, the equation the line joining two points(5,-3 ) adn(7,-4 ) is  x+2y=-1

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