Question

find the equation of straight line passing through points (-2, 3) & (4, -6)​

Answer 1

Answer:

The equation of a line passing through the points (2, 3) and (4, 6) is 3x - 2y = 0.

Step-by-step explanation:

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Answer 2

The equation of the line is 3x + 2y = 0

Given :

The points ( - 2, 3) & (4, - 6)

To find :

The equation of the line passing through the points

Solution :

Step 1 of 2 :

Write down the given points

The given points are ( - 2, 3) & (4, - 6)

Step 2 of 2 :

Find the equation of the line

The required equation of the line is

$\displaystyle \sf{ \frac{y - 3}{x - ( - 2)} = \frac{ - 6 - 3}{4 - ( - 2)} }$

$\displaystyle \sf{ \implies \frac{y - 3}{x + 2} = \frac{ - 6 - 3}{4 + 2} }$

$\displaystyle \sf{ \implies \frac{y - 3}{x + 2} = \frac{ - 9}{6} }$

$\displaystyle \sf{ \implies \frac{y - 3}{x + 2} = \frac{ - 3}{2} }$

$\displaystyle \sf{ \implies 2y - 6 = - 3x - 6}$

$\displaystyle \sf{ \implies 3x + 2y - 6 + 6=0}$

$\displaystyle \sf{ \implies 3x + 2y=0}$

The equation of the line is 3x + 2y = 0