Question

Find the equation of straight line passing through the points ( 2,1) and through points of intersection of lines x+2y = 3 and 2x-3y= 4 .

Answer 1

Heya.......!!!

Equation of any straight line passing through the intersection of the lines » x + 2y = 3 ,,,, 2x - 3y = 4 is >>>>>

k ( x + 2y - 3 ) + ( 2x - 3y -4 ) = 0 ............[ eq 1 ]

Since it passes through point ( 2, 1 )

»» k ( 2+2-3 ) + ( 4-3-4 ) = 0
k - 3 = 0
k = 3 .

Now substituting this value of k in eq 1 , we get
3 ( x + 2y - 3 ) + ( 2x - 3y - 4 ) = 0

➡5x + 3y - 13 = 0 ,,, This is the required equation of straight line .

HOPE IT HELPS U